How is the graph of y=9 (3) ^x-2 - 6 translated from the graph of y=9 (3) ^x?

For this case we have the following function:

y = 9 (3) ^ x

Applying the following transformations we have:

Horizontal translations

Suppose that h> 0

To graph y = f (x-h), move the graph of h units to the right.

y = 9 (3) ^ (x-2)

Vertical translations

Suppose that k> 0

To graph y = f (x) - k, move the graph of k units down.

y = 9 (3) ^ (x-2) - 6

Answer:

2 units to the right

6 units down

The question to this answer is ham