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18 November, 11:41

Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n equals 125n=125 , p equals 0.46

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  1. 18 November, 14:46
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    This is a matter of knowing the formulas involving the binomial distribution: Mean = n*p = 125*0.46 = 57.5

    Variance = n*p * (1-p) = 125*0.46 * (1-0.46) = 125*0.46*0.54 = 31.05

    Standard Deviation = sqrt (Variance) = sqrt (31.05) = 5.572252686
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