What is the range of f (x) = 2x squared-2x+5 if the domain is (-2, - 1, 0, 1, 2) ?

Plug in the 5 values in the domain

f (-2) = 2 (-2) ^2 - 2 (-2) + 5 = 8+4+5 = 17 so first number in the range is 17.

f (-1) = 2 (-1) ^2 - 2 (-1) + 5 = 2 + 2 + 5 = 9

f (0) = 0 - 2 + 5 = 5

fond f (1) and f (2) in the same way

results are 17,9,5,5,9

so the range is {5, 9,17} (you don't repeat values)