Find the absolute maximum and absolute minimum values of f on the given interval. f (x) = ln (x2 + 5x + 12), [-3, 1]

A graphing calculator shows the minimum to be located at the vertex of the quadratic, x = - 2.5, and the maximum to be located at the right end of the interval.

The absolute maximum value of f (x) is ln (18) ≈ 2.89037.

The absolute minimum value of f (x) is ln (5.75) ≈ 1.74920.