Ask Question
29 April, 19:30

Juan has c cheesecakes. Clarence has 5 less than 3 times as many cheesecakes as Juan has and Darlene has 2 more than half as many cheesecakes as Clarence has. Find an expression in terms of $c$ for the total number of cheesecakes Juan, Clarence, and Darlene have.

+3
Answers (1)
  1. 29 April, 22:46
    -2
    C = Clarence, J = Juan, and D = Darlene

    C = 3J-5

    D = C/2+2

    J = c
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Juan has c cheesecakes. Clarence has 5 less than 3 times as many cheesecakes as Juan has and Darlene has 2 more than half as many ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers