Ask Question
30 December, 10:30

This is section 3.8 problem 16: a landscape architect plans to enclose a 2,500 square feet rectangular region in a botanical garden. she will use shrubs costing 18 dollar per foot along three sides and fencing costing 32 dollars per foot along the fourth side. find the dimensions of the botanical garden that will minimize the total cost. follow the steps:

+3
Answers (1)
  1. 30 December, 10:35
    0
    The cost function is given by:

    Total Cost = 32w + 18 (w + 2l) = 50w + 36l

    Where,

    w: width

    l: long

    The area is given by:

    Area = w * l = 2500

    We cleared l:

    l = 2500 / w

    We leave the cost function in terms of a variable:

    Cost = 50w + 36 (2500 / w) = 50w + 90000 / w

    We now look for the derivative of the function:

    C ' (w) = 50 - 90000 / w² = 0

    50 = 90000 / w²

    50w² = 90000

    w² = 90000/50

    w² = root (90000/50)

    w = 42.43 feet

    We look for the other dimension:

    l = 2500 / (42.43)

    l = 58.92 feet

    Minimum cost:

    C (42.43) = 50 * (42.43) + 36 * (2500 / 42.43) ≈ $ 4242.64

    Answer:

    The dimensions of the botanical garden that will minimize the total cost are:

    w = 42.43 feet

    l = 58.92 feet

    The cost is:

    $ 4242.64
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “This is section 3.8 problem 16: a landscape architect plans to enclose a 2,500 square feet rectangular region in a botanical garden. she ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers