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2 April, 18:19

The rate of change of y with respect to t is proportional to 50 - y

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  1. 2 April, 21:31
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    We can write and solve the differential equation that fits the statement given;

    dy/dt = k (50-t)

    ∫dy = ∫ k (50-t) dt

    = ∫ (50k - kt) dt

    therefore;

    y = 50kt - k/2 (t²) + C

    Alternatively, can be written as

    y = - k/2 (50-t) ² + C)
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