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26 April, 22:14

Suppose a triangle has two sides of the length 2and 3 and that the angle between these two sides is 60 what is the length of the third side of the triangle

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  1. 26 April, 23:43
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    Let the given sides be "a" and "b" and the unknown side be "c". The Law of Cosines tells you

    ... c^2 = a^2 + b^2 - 2ab*cos (C)

    ... c^2 = 2^2 + 3^2 - 2*2*3*cos (60°)

    ... c^2 = 7

    ... c = √7 ≈ 2.6458

    The third side of the triangle is √7, about 2.6458.
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