The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?

A. 3a=48

B. a (a+1) (a+2) = 48

C. a + (a-1) + (a-2) = 48

D. a + (a+1) + (a+2) = 48

Question

Mathematics

Ralph

30 August, 15:53

The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?

A. 3a=48

B. a (a+1) (a+2) = 48

C. a + (a-1) + (a-2) = 48

D. a + (a+1) + (a+2) = 48

+5

Answers (2)

Know the Answer?

Kenley Herrera · Answer 1

D. a + (a + 1) + (a + 2) = 48

The ages of the friends are 15, 16, and 17

Layton Dodson · Answer 2

Three consecutive numbers ... a, a + 1, a + 2

together their ages total 48 years

a + (a + 1) + (a + 2) = 48 < = = ur equation

3a + 3 = 48

3a = 48 - 3

3a = 45

a = 45/3

a = 15

a + 1 = 15 + 1 = 16

a + 2 = 15 + 2 = 17

so their ages are : 15,16,17

The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?A. 3a=48B. a (a+1) (a+2) = 48C. a + (a-1) + (a-2) = 48D. a + (a+1) + (a+2) = 48

The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?

A. 3a=48

B. a (a+1) (a+2) = 48

C. a + (a-1) + (a-2) = 48

D. a + (a+1) + (a+2) = 48