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7 January, 13:52

If you solve for x in x^2 = 25, you get two solutions 5 and - 5

If you solve for x in x^3=125, would x have three solutions?

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  1. 7 January, 17:25
    0
    No

    the answer is 5, only 1 solution

    because - 5*-5*-5 is - 125
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