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3 July, 05:59

Q and R are not mutually exclusive events. If P (Q) = 5/8 and P (R) = 1/8 and P (Q and R) = 1/32, Find P (q or R)

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  1. 3 July, 06:48
    0
    The solution for this problem is just adding and subtracting fractions. We all know how to add and subtract function because our teacher since high school teach us how to. P (Q or R) = P (Q) + P (R) - P (Q and R) = 5/8 + 1/8 - 1/32 = 23/32

    The answer to this question is 23/32.
  2. 3 July, 07:20
    0
    Given that the events are not mutually exclusive the union of the probability of the events is calculated through the equation,

    P (Q or R) = P (Q) + P (R) - P (Q and R)

    Substituting the known values,

    P (Q or R) = 5/8 + 1/8 - 1/32

    Simplifying,

    P (Q or R) = 23/32

    The answer to this item is 23/32.
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