The mechanics at Lincoln Automotive are reboring a 6-in deep cylinder to fit a new piston. The machine they are using increases the cylinders radius one-thousandth of an inch every 4min. How rapidly is the cylinder volume increasing when the bore (diameter) is 3.800in ... ?

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21 April, 07:17

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Noe Alexander · Answer 1

Dr/dt = 0.00025/min

V = πr^2h

dV/dt = 2πrh dr/dt

Here, r = 3.8/2 = 1.9, h = 6

dV/dt = 2π (1.9) (6) (0.00025) = 0.00285π = 0.00895 in^2/min