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14 May, 21:57

If cos θ = 5/13, use the Pythagorean Identity to find sin θ.

13/13

12/13

12/5

5/13

+2
Answers (1)
  1. 15 May, 01:34
    0
    Sin θ=sqrt (1 - cos^2 θ)

    sin θ=sqrt[1 - (5/13) ^2]

    sin θ=sqrt[1 - (5) ^2 / (13) ^2]

    sin θ=sqrt[1-25/169]

    sin θ=sqrt[ (169-25) / 169]

    sin θ=sqrt (144/169)

    sin θ=sqrt (144) / sqrt (169)

    sin θ=12/13

    Answer: Second option 12/13
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