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16 May, 05:16

Two tourists left two towns, the distance between which is 38 km, simultaneously and met in 4 hours. what was the speed of each of the tourists, if the first one covered 2 km more before he met than the second one?

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  1. 16 May, 07:08
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    Let the relative speed will be given by:

    38/4=9.5 km/h

    Let the speed of the first tourist be x km/h

    the speed of the second one is (9.5-x) km/h

    distance covered by the first one is:

    4*x+2=4x+2 km

    distance covered by the second one is:

    (9.5-x) 4 km

    = (38+4x) km

    total distance will be given by:

    (38+4x) + (4x+2) = 38

    40+8x=38

    8x=-2

    x=-1/4 km/h

    this mean that he was traveling in the opposite direct thus the speed was 1/4 km/k

    The speed of the second one will be:

    9.5-1/4=9.25 km/h
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