Write an equation for the line perpendicular to 2x-3y = 5 and containing (-2, 1).

Hello:

the equation is : y = ax+b

the slope is a : a * (2/3) = - 1 ... (perpendicular to a line : 2x-3y = 7 with a slope of 2/3 because : y = (2/3) x-7/3)

a = - 3/2 y = (-3/2) x+b

the line that passes through (-2, 1) : 1 = (-3/2) (-2) + b

b = - 2

the equation is : y = (-3/2) x-2