The measure of one angle is eleven more than four times a number another angle is twice the first angles measure the sum of the measures of the angles are 195 degrees what is the measure of each angle

X, y, and z are the angles

so

x is 11 more than 4 times y

x=11+4y

z is twice the first angles measure

z=2x

the sum of the angles is 195

x+y+z=195

so we have

x=11+4y

z=2x

and

x+y+z=195

make everything y

subsitute 11+4y for x

11+4y+y+z=195

subsitute 2x for z

11+4y+y+2x=195

subsitute 11+4y for x

11+4y+y+2 (11+4y) = 195

distribute

11+4y+y+22+8y=195

group according to type

(4y+y+8y) + (11+22) = 195

add like terms

13y+33=195

subtract 33 from both sides

13y=162

divide both sides by 13

y=12 and 8/13

subsitute

x=11+4y

x=11+4 (12 and 6/13)

x=11+48 and 24/13

x=11+49 and 11/13

x=60 and 11/13

z=2x

z=2 (60 and 11/13)

z=120 and 22/13

z=121 and 9/13

the angles are

12 and 6/13

60 and 11/13

121 and 9/13 or aprox

12.46

60.85

121.69

Answer=65° & 130°

195°=angle1+angle2

195° = (11+4x) + 2 (11+4x)

195°=33+12x

subtract 33 for both sides

162=12x

13.5=x

Now lets solve for the measure of the angles

angle1=11+4x

angle1=11+4 (13.5)

angle1=11+54

angle1=65°

angle2=2 (11+4x)

angle2=2 (11+4 (33.5))

angle2=2 (11+54)

angle2=2 (65)

angle2=130°