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6 July, 00:51

How many solutions does the equation have?

4 (z-5) + 2=4z-18

+5
Answers (2)
  1. 6 July, 01:09
    0
    All real numbers is the solution of this equation

    4z - 20 + 2 = 4z - 18

    4z - 18 = 4z - 18

    +18 + 18

    4z = 4z
  2. 6 July, 01:28
    0
    Distribute the 4:

    4z - 20 + 2 = 4z - 18

    Subtract 4z

    -20 + 2 = - 18

    -18 = - 18

    This is true so that means there are infinite number of solutions ... z could be anything!
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