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27 May, 03:20

10x-35+3ax=5ax-7a solve for "a" for which the equation is an identity.

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  1. 27 May, 05:12
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    10x-35+3ax=5ax-7a

    10x-35=5ax-7a-3ax

    10x-35=a (5x-7-3x)

    (10x-35) / (5x-7-3x) = a

    therefore a = (10x-35) / (5x-7-3x)
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