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10 June, 09:09

The law of cosines is a2+b2 - 2abcosC = c^2 find the value of 2abcosC ... A. 40 B. - 40 C. 37 D. 20

(The sides are 2,4, and 5; A to B is 2, B to C is 4, and A to C is 5.)

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  1. 10 June, 10:04
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    A² + b² - 2abcosC = c²

    Аngle C lies opposite to the side AB, so "c" in the formula it is AB in your triangle

    4² + 5² - 2abcosC = 2²

    16 + 25 - 2abcosC = 4

    41 - 4 = 2abcosC

    2abcosC = 37
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