What are the x intercepts of this function f (x) = 2x^2-7x-4?

2x² - 7x - 4 = 0

2x² - 8x + x - 4 = 0

2x (x - 4) + 1 (x - 4) = 0

(2x + 1) (x - 4) = 0

Set each binomial equal to zero.

2x + 1 = 0

2x = - 1

x = - 1/2

x - 4 = 0

x = 4

Your x-intercepts are x = - 1/2, 4 or ( - 1/2, 0) and (4, 0)