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13 May, 21:01

What are the x intercepts of this function f (x) = 2x^2-7x-4?

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  1. 14 May, 00:42
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    2x² - 7x - 4 = 0

    2x² - 8x + x - 4 = 0

    2x (x - 4) + 1 (x - 4) = 0

    (2x + 1) (x - 4) = 0

    Set each binomial equal to zero.

    2x + 1 = 0

    2x = - 1

    x = - 1/2

    x - 4 = 0

    x = 4

    Your x-intercepts are x = - 1/2, 4 or ( - 1/2, 0) and (4, 0)
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