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12 October, 07:00

find the solution set

a^2-8a+12=0

separate the two values with a comma

+3
Answers (2)
  1. 12 October, 08:57
    0
    A^2-8a+12=0 (this is of the form ax^2+bx+c)

    find jk=ac=12 and j+k=b=-8, then j and k must be - 2 and - 6

    now replace - 8a with - 2a and - 6a

    a^2-2a-6a+12=0 now factor 1st and 2nd pair of terms ...

    a (a-2) - 6 (a-2) = 0 which is equal to

    (a-6) (a-2) = 0

    So a = (2, 6)
  2. 12 October, 10:13
    0
    Hi again

    a² - 8a + 12 = 0

    Factor left side

    (a - 2) (a - 6) = 0

    Now we should set factors equal to 0

    a - 2 = 0 or a - 6 = 0

    a = 0 + 2 0r a = 0 + 6

    a = 2 or a = 6

    Answer : A = 2 or a = 6 >>> (2,6)
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