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19 February, 00:16

What is the solution to this system of equations? {5x+4y=22 3x+4y=10

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  1. 19 February, 02:11
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    Multiply 2nd equqation by - 1 and add to first

    5x+4y=22

    -3x-4y=-10 +

    2x+0y=12

    2x=12

    divide by 2

    x=6

    sub back

    3x+4y=10

    3 (6) + 4y=10

    18+4y=10

    minus 18 both sides

    4y=-8

    divide by 4

    y=-2

    (x, y)

    (6,-2) is solution
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