Suppose a least-squares regression line is given by modifyingabove y with caret equals 4.302 x minus 3.293y=4.302x-3.293. what is the mean value of the response variable if x equals 20x=20

We are given the following relation:

y = 4.302 x - 3.293

To solve for the mean value of y when x = 20, what we have to do is to find for the value of y at x = 20 and the value of y at x = 0. Then we get the average of the two values.

when x = 0

y (0) = 4.302 (0) - 3.293

y (0) = - 3.293

when x = 20

y (20) = 4.302 (20) - 3.293

y (20) = 82.747

The mean value would be:

mean y = [y (20) + y (0) ] / [20 + 0]

mean y = [82.747 + (-3.293) ] / 20

mean y = 3.9727 = 3.97