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13 January, 19:18

how do ypu slove dis?

y^2 (q-4) - c (q - 4)

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  1. 13 January, 21:33
    0
    y2 (q-4) - c (q-4) Final result : (q - 4) • (y2 - c)

    Step by step solution : Step 1 : Equation at the end of step 1 : ((y2) • (q - 4)) - c • (q - 4) Step 2 : Equation at the end of step 2 : y2 • (q - 4) - c • (q - 4) Step 3 : Pulling out like terms:

    3.1 Pull out q-4

    After pulling out, we are left with:

    (q-4) • (y2 * 1 + (c * (-1)))

    Trying to factor as a Difference of Squares:

    3.2 Factoring: y2-c

    Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

    Proof : (A+B) • (A-B) =

    A2 - AB + BA - B2 =

    A2 - AB + AB - B2 =

    A2 - B2

    Note : AB = BA is the commutative property of multiplication.

    Note : - AB + AB equals zero and is therefore eliminated from the expression.

    Check : y2 is the square of y1

    Check : c1 is not a square!

    Ruling : Binomial can not be factored as the difference of two perfect squares

    Final result : (q - 4) • (y2 - c)
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