how do ypu slove dis?

y^2 (q-4) - c (q - 4)

y2 (q-4) - c (q-4) Final result : (q - 4) • (y2 - c)

Step by step solution : Step 1 : Equation at the end of step 1 : ((y2) • (q - 4)) - c • (q - 4) Step 2 : Equation at the end of step 2 : y2 • (q - 4) - c • (q - 4) Step 3 : Pulling out like terms:

3.1 Pull out q-4

After pulling out, we are left with:

(q-4) • (y2 * 1 + (c * (-1)))

Trying to factor as a Difference of Squares:

3.2 Factoring: y2-c

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : y2 is the square of y1

Check : c1 is not a square!

Ruling : Binomial can not be factored as the difference of two perfect squares

Final result : (q - 4) • (y2 - c)