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19 June, 15:01

The driver of a car traveling at 54ft/sec suddenly applies the brakes. The position of the car is s=54t-3t^2, t seconds afyer the driver applies the brakes.

How many seconds after the driver applies the brakes does the car come to a stop

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  1. 19 June, 16:52
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    s = 60t - 3t^2

    v = ds/dt = 60 - 6t

    when it comes to rest, v = 0,

    so t = 10 sec

    now distance travelled = time taken x average velocity

    = 10 x (60 + 0) / 2

    = 300 ft
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