An oil storage tank ruptures at time t = 0 and oil leaks from the tank at a rate of r (t) = 85e-0.04t liters per minute. How much oil leaks out during the first hour? (Round your answer to the nearest liter.)

Given the rate of water flow is given by:

r (t) = 85e^ (-0.04t)

thus the amount of water flow in the first hour when t=1, will be:

r (1) = 85e^ (-0.04*1)

=81.667

thus the amount of water that flowed out will be:

85-81.667

=3.333 liters