Ask Question
12 April, 18:21

Find the 10th term of the following geometric sequence: 2, 8, 32, 128. A. 164,357 B. 621,325 C. 524,288 D. 248,221

+1
Answers (1)
  1. 12 April, 21:40
    0
    Common ratio = 8/2 = 32/8 = 4

    10th term = a1*r^ (n - 1) where a1 = 2, r = 4 and n = 10

    = 2 * 4^9

    = 524,288
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Find the 10th term of the following geometric sequence: 2, 8, 32, 128. A. 164,357 B. 621,325 C. 524,288 D. 248,221 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers