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25 December, 11:25

Suppose we want to choose 3 letters without replacement from the 4 letters a, b, c and d, how many ways can this be done if the choice matters or does not matter

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  1. 25 December, 13:53
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    it is the number of permutations that are possible when arranging k k ... You must choose two, without replacement, where order matters ... Here are lots of different names for this number: 5P2=5⋅ 4=5⋅4⋅3!3! ... How many ways are there to choose two letters from five letters (without ... Then, n C k=nPkk!
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