A group of friends will be buying at most 10 items at the concession stand at the high school football game. They have no more than $25 to spend at the game. Each hot food item is #3 and each cold food item is $2. The system of inequality graphed below represents this information. Which combination of hot and cold food items could the group buy? 0 hot items and 11 cold items, 9 hot items and 1 cold item, 2 hot items and 8 cold items, 6 hot items and 4 cold items

0 hot items and 11 cold items

Step-by-step explanation:

He has 25 dollars to spend.

Hot: 3

Cold: 2

Let's eliminate some wrong answers.

1. 0 hot items and 11 cold items: Possible, because 11 times 2 is 22.

2. 9 hot items and 1 cold item: Impossible, because 9 times 3 = 27 and that is already over 25 dollars. This one is eliminated.

3. 2 hot items and 8 cold items: 2 times 3 is 6. 8 times 2 is 16. 16 + 3 = 19. He buys 10 items here. Selection one bought 11 items though, so this one is eliminated.

4. 6 hot items and 4 cold items: 6 times 3 is 18, and 4 times 2 is 8. 18 + 8 = 26. He doesn't have enough money, so this one is eliminated.

0 hot items and 11 cold Items

Step-by-step explanation:

The other combinations will be more than $25 but

11 (3) = 22 which is even lower than $25