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13 May, 20:42

A bag contains 3 red marbles, 2 blue marbles, and 5 green marbles. What is the probability of selecting a red marble, replacing it in the bad and then selecting a green marble

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  1. 13 May, 23:46
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    3/20

    Step-by-step explanation:

    The total number of marbles is

    3 red marbles + 2 blue marbles + 5 green marbles = 10 marbles

    P (1st marble is red) = red marbles/total

    =3/10

    We replace the marble so there are still 10 marbles in the bag

    P (2nd marble is green) = green marbles/total

    =5/10 = 1/2

    P (1st red, 2nd green) = P (1st marble is red) * P (2nd marble is green)

    =3/10 * 1/2

    =3/20
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