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13 March, 08:58

The temperature of chicken soup is 192.7 degrees F. As it cools, the temperature of the soup decreases 2.3 degrees F per minute. What is the temperature of the soup after 25 minutes?

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Answers (2)
  1. 13 March, 11:09
    0
    Answer:the temperature of the soup after 25 minutes is 137.5 degrees

    Step-by-step explanation:

    As it cools, the temperature of the soup decreases 2.3 degrees F per minute. This is a linear rate. The rate at which the temperature is decreasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

    Tn = a + (n - 1) d

    Where

    a represents the first term of the sequence.

    d represents the common difference.

    n represents the number of terms in the sequence.

    From the information given,

    a = 192.7 degrees

    d = - 2.3 degrees (it is decreasing)

    n = 25

    We want to determine the value if the 25th term, T25. Therefore,

    T25 = 192.7 - 2.3 (25 - 1) = 192.7 - 2.3*24

    T25 = 137.5 degrees
  2. 13 March, 11:59
    0
    The answer to your question is Final temperature = 135.2 °F

    Step-by-step explanation:

    Data

    Initial temperature = T₀ = 192.7°F

    Rate of decreasement = 2.3°F x t

    Final temperature = T₂ = ?

    Final time = t₂ = 25 min

    Process

    1. - Write an equation

    T₂ = T₀ - 2.3 t₂

    2. - Substitute values given in the formula

    T₂ = 192.7 - (2.3 x 25)

    3. - Simplify and result

    T₂ = 192.7 - 57.5

    T₂ = 135.2 °F
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