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18 February, 21:21

If p (x) = x2 - 1 and q (x) = 5 (x minus 1), which expression is equivalent to (p - q) (x) ?

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Answers (2)
  1. 18 February, 21:31
    0
    All you need to do p (x) - q (x). So:

    (x^{2}-1) - (5) (x-1)

    That's it!
  2. 18 February, 21:37
    0
    Step-by-step explanation:

    P (x) = x² - 1 and Q (x) = 5 (x - 1)

    (P - Q) (x) = x² - 1 - 5 (x - 1)

    = x² - 1 - 5x + 5

    = x² - 5x + 4
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