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29 March, 05:04

Solve x³-2x²-5x+6=0

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  1. 29 March, 06:13
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    x³ - 2x² - 5x + 6 = 0

    x³ - x² - x² + x - 6x + 6 = 0

    x² (x - 1) - x (x - 1) - 6 (x - 1) = 0

    (x - 1) (x² - x - 6) = 0

    (x - 1) (x² + 2x - 3x - 6) = 0

    (x - 1) [x (x + 2) - 3 (x + 2) ] = 0

    (x - 1) (x + 2) (x - 3) = 0

    x - 1 = 0 = > x₁ = 1

    x + 2 = 0 = > x₂ = - 2

    x - 3 = 0 = > x₃ = 3
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