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16 August, 01:02
Solve for b by elimination 2a+3b=12
5a-b=13
+1
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Maverick Roth
16 August, 03:02
0
Answer: 2a+3b=12
b = (12-2a) / 3
5a-b=13
b = - 13+5a
Step-by-step explanation:
1) 2a+3b=12
-2a - 2a
3b=12-2a
/3 / 3
b = (12-2a) / 3
2) 5a-b=13
-5a - 5a
-b=13-5a
*-1 * -1 - b = 13 (-1) - 5a (-1) * you'd multiply by - 1 to cancel out the negative on b*
b = - 13+5a
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