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16 August, 01:02

Solve for b by elimination 2a+3b=12

5a-b=13

+1
Answers (1)
  1. 16 August, 03:02
    0
    Answer: 2a+3b=12

    b = (12-2a) / 3

    5a-b=13

    b = - 13+5a

    Step-by-step explanation:

    1) 2a+3b=12

    -2a - 2a

    3b=12-2a

    /3 / 3

    b = (12-2a) / 3

    2) 5a-b=13

    -5a - 5a

    -b=13-5a

    *-1 * -1 - b = 13 (-1) - 5a (-1) * you'd multiply by - 1 to cancel out the negative on b*

    b = - 13+5a
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