Find the fifth term of the arithmetic sequence whose third term is 29 and

common difference is 10.

The third term of the arithmetic sequence is 49

Step-by-step explanation:

It's 49 because:

as you said the third term is 29 and common difference is 10, so I add the common difference to the every answer that I get as it shown below:

29+10=39 (this is the fourth term)

39+10=49 (this is the fifth term)

The 1st, 2nd, 3rd, 4th and 5th are shown below:

9,19,29,39,49

Answer: The fifth term is 49.

Step-by-step explanation: The question states that what we have is an arithmetic sequence. The nth term of an arithmetic sequence is defined as;

Nth term = a + (n - 1) d

Where a is the first term,

n is the nth or unknown term and

d is the common difference

The common difference has been given as 10, and the 3rd term has been given as 29. The first term is yet unknown. We can now express the 3rd term as follows;

29 = a + (3 - 1) x 10

29 = a + 2 (10)

29 = a + 20

Subtract 20 from both sides of the equation

a = 9

Having calculated the first term a to be equal to 9, we can now solve for the 5th term as follows;

nth term = a + (n - 1) d

5th term = 9 + (5 - 1) x 10

5th term = 9 + (4) x 10

5th term = 9 + 40

5th term = 49.