Ask Question
27 February, 04:15

what is the equation of the quadratic graph with a focus of (-1,4) and a directrix of y=2? hint: y=a (x-h) ^2+k, a=1/4p

+1
Answers (1)
  1. 27 February, 05:26
    0
    y = 1/4 (x + 1) ^2 + 3.

    Step-by-step explanation:

    The general form is (x - h) ^2 = 4p (y - k) where the focus is (h, k+p) and the directrix is y = k-p

    So we have h = - 1

    k + p = 4

    k - p = 2 Adding:

    2k = 6 so k = 3 and p = 1.

    Therefore:

    (x + 1) ^2 = 4 (y - 3)

    4y = (x + 1) ^2 + 12

    y = 1/4 (x + 1) ^2 + 3.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “what is the equation of the quadratic graph with a focus of (-1,4) and a directrix of y=2? hint: y=a (x-h) ^2+k, a=1/4p ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers