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26 September, 14:58

En el triángulo rectángulo ABC, recto en "B", SI Tg C = 3/5, hallar el valor "cosec A"

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  1. 26 September, 15:34
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    Answer: Cosec (A) = 3.64

    Step-by-step explanation:

    Ok, tenemos un triangulo rectángulo.

    Sabemos que B = 90° y que

    tg (C) = 3.5

    entonces:

    Atg (Tg (C)) = C = Atg (3.5) = 74.05°.

    Nosotros también sabemos que la suma de todos los ángulos interiores de un triangulo es igual que 180°

    entonces:

    A + B + C = 180°

    A + 90° + 74.05° = 180°

    A = 180° - 90° - 74.05° = 15.95°

    Entonces Cosec (A) = Cosec (15.95°) = 1/sin (15.95°) = 3.64
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