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8 June, 18:28

The quadratic equation x^{2}-6x=12 is rewritten in the form (x+p) ^2=q, where q is a constant. What is the value of p?

+3
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  1. 8 June, 20:41
    0
    p = - 3

    Step-by-step explanation:

    Given

    x² - 6x = 12

    To obtain the required form use the method of completing the square

    add (half the coefficient of the x - term) ² to both sides, thus

    x² + 2 ( - 3) x + 9 = 12 + 9

    (x - 3) ² = 21

    Thus p = - 3
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