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6 March, 11:25

A train leaves Miami at 3:00 PM. A second train leaves the same city in the same direction at 5:00 PM. The second train travels 50mph faster than the first. If the second train overtakes the first at 7:00 PM, what is the speed of each of the two trains?

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  1. 6 March, 14:09
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    Answer: the speed of the first train is 50 mph.

    The speed of the second train is 100 mph.

    Step-by-step explanation:

    Let x represent the speed of the first train. The second train travels 50mph faster than the first. It means that the speed of the second train is (x + 50) mph.

    Distance = speed * time

    If the second train overtakes the first at 7:00 PM, it means that both trains covered the same distance by 7:00 PM. The first train left Miami at 3:00PM. Time spent by the first train is 7 - 3 = 4 hours

    Distance covered by the first train in 4 hours is 4x

    The second train left at 5:00 PM. Time spent by the second train is 7 - 5 = 2 hours

    Distance covered by the second train in 2 hours is 2 (x + 50)

    Therefore,

    4x = 2 (x + 50)

    4x = 2x + 100

    4x - 2x = 100

    2x = 100

    x = 100/2

    x = 50 mph

    The speed of the second train is

    x + 50 = 50 + 50 = 100 mph
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