if log 2 = a, log 3 = b, and log 7 = c what is log 490 in terms of a, b and c and you can have integer coefficients

Answer is 2*c + log [10^{a} + 10^{b}] + a

Step-by-step explanation:

log 2 = a, log 3 = b, log 7 = c

Using formula

log d*e = log d + log e

log d^{a} = a*log d

log 5 = log [10^{a} + 10^{b}]

log 490 in terms of a, b and c and you can have integer coefficients

log 490

= log 7^{2}*5*2

= 2*log 7 + log 5 + log 2

= 2*c + log [10^{a} + 10^{b}] + a

Answer is 2*c + log [10^{a} + 10^{b}] + a