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21 September, 06:13

Randall wants to mix 44 lb of nuts worth $1 per lb with some nuts worth $9 per lb to make a mixture worth $8 per lb. How many pounds of $9 nuts must he use?

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  1. 21 September, 06:35
    0
    38.5 pounds

    Step-by-step explanation:

    Let pounds of $1 nuts used be "x"

    Let pounds of $9 nuts used be "y"

    44 lb of nuts in total, so we can say:

    x + y = 44

    or

    x = 44 - y

    Now, the mixture of 44 lb nuts would be worth $8, so we can write:

    1x + 9y = 8 (44)

    x + 9y = 352

    We replace this with the 1st equation (x = 44 - y) and find the value of "y":

    x + 9y = 352

    44 - y + 9y = 352

    8y = 352 - 44

    8y = 308

    y = 308/8

    y = 38.5

    So, we need to mix 38.5 pounds of $9 nuts
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