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6 April, 19:07

Use the discriminant to determine how many solutions are possible for the following equation show

work)

5x^2-3x+4=0

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Answers (1)
  1. 6 April, 21:53
    0
    x = 3/10 + (i sqrt (71)) / 10 or x = 3/10 - (i sqrt (71)) / 10

    Step-by-step explanation:

    Solve for x:

    5 x^2 - 3 x + 4 = 0

    Divide both sides by 5:

    x^2 - (3 x) / 5 + 4/5 = 0

    Subtract 4/5 from both sides:

    x^2 - (3 x) / 5 = - 4/5

    Add 9/100 to both sides:

    x^2 - (3 x) / 5 + 9/100 = - 71/100

    Write the left hand side as a square:

    (x - 3/10) ^2 = - 71/100

    Take the square root of both sides:

    x - 3/10 = (i sqrt (71)) / 10 or x - 3/10 = - (i sqrt (71)) / 10

    Add 3/10 to both sides:

    x = 3/10 + (i sqrt (71)) / 10 or x - 3/10 = - (i sqrt (71)) / 10

    Add 3/10 to both sides:

    Answer: x = 3/10 + (i sqrt (71)) / 10 or x = 3/10 - (i sqrt (71)) / 10
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