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18 January, 05:48

In how many ways can 8 people be seated in a row if (a) there are no restrictions on the seating arrangement? (b) persons A and B must sit next to each other? (c) there are 4 men and 4 women and no 2 men or 2 women can sit next to each other? (d) there are 5 men and they must sit next to each other? (e) there are 4 married couples and each couple must sit together?

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  1. 18 January, 06:20
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    a) P (8) = 40320

    b) Pt (7) = 10080

    c) P (t) = 48

    d) P (4) = 24

    e) P (4) = 24

    Step-by-step explanation:

    a) Without restrictions 8 persons can seat according to

    P (8) = 8! P (8) = 8*7*6*5*4*3*2*1

    P (8) = 40320

    b) Two people must sit next to each other

    Let A and B are a unit in the group

    Then we have 7 elements

    P₁ (7) = 7! P₁ (7) = 7*6*5*4*3*2*1

    P₁ (7) = 5040

    Now this number is for arrangement A B we should add the same number now with B A

    Then P₂ (7) = 5040 and

    Pt (7) = 10080

    c) There are 4 men and 4 women that can not sit next to each other

    Let A B C and D stands for men and 1 2 3 and 4 women

    A 1 B 2 C 3 D 4

    This kind of arrangement is what we are loking for

    If we change men and women are still we have

    P₁ (4) = 4! P₁ (4) = 4*3*2*1

    P₁ (4) = 24

    Now we dont move men but women

    P₂ (4) = 24

    In this case P (t) = 24+24

    P (t) = 48

    d) If five men is a group we have only 4 elements

    P (4) = 4! P (4) = 4*3*2*1

    P (4) = 24

    e) If we have four couples we only have four elements

    P (4) = 24
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