If the sides of a triangle have measures 3x + 4, 6x - 1 and 8x + 2, find all possible values of x.

Question 12 options:

a)

x > - 4/3

b)

0 < x < 1/6

c)

1/6 < x < 3/11

d)

x > 0

Question

Mathematics

Keegan

13 April, 13:42

If the sides of a triangle have measures 3x + 4, 6x - 1 and 8x + 2, find all possible values of x.

Question 12 options:

a)

x > - 4/3

b)

0 < x < 1/6

c)

1/6 < x < 3/11

d)

x > 0

+5

Answers (2)

Know the Answer?

Kenzie Warner · Answer 1

Kenzie Warner 13 April, 16:02

0

Answer: x>-4/3 is correct.

Milo Wong · Answer 2

Answer: x>-4/3

Step-by-step explanation:All sides must be greater of zero:

3x+4>0

3x> - 4 Divide with 3

x> - 4/3

6x-1>0

6x>1 Divide with 6

x>1/6

8x+2>0

8x> - 2 Divide with 8

x> - 2/8

x> - 1/4

Least of that numbers is - 4/3 = - 1.3333

x> - 4/3 is solution

If the sides of a triangle have measures 3x + 4, 6x - 1 and 8x + 2, find all possible values of x.Question 12 options:a)x > - 4/3b)0 < x < 1/6c)1/6 < x < 3/11d)x > 0

If the sides of a triangle have measures 3x + 4, 6x - 1 and 8x + 2, find all possible values of x.

Question 12 options:

a)

x > - 4/3

b)

0 < x < 1/6

c)

1/6 < x < 3/11

d)

x > 0