What are the zeros of the quadratic function f (x) = 2x^2+8x-3

-2 + / - [ (sqrt 88) / 4]

or

0.35, - 4.35 to the nearest hundredth.

Step-by-step explanation:

2x^2 + 8x - 3 = 0

Using the quadratic formula:

x = [ - 8 + / - sqrt (8^2 - 4*2*-3) ] / 4

= - 2 + / - (sqrt 88) / 4