Factor the expression.

6g2 + 11g - 35

A (3g + 5) (2g + 7)

B (3g + 5) (28 - 7)

C (38 - 5) (28 - 7)

D (38 - 5) (2g + 7)

It's meant to be (3g-5) (2g+7)

(3g - 5) (2g + 7).

Step-by-step explanation:

6g^2 + 11g - 35 Use the 'ac' method:

6 * - 35 = - 210. We need 2 numbers whose product is - 140 and whose sum is + 11.

+ 21 and - 10 fit the bill, so we can write:

6g^2 + 21g - 10g - 35

= 3g (2g + 7) - 5 (2g + 7)

= (3g - 5) (2g + 7).