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26 April, 18:27

13. Solve: 3x² + 11x + 5<9

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  1. 26 April, 18:40
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    -4
    Step-by-step explanation:

    3x²+11x+5<9

    3x²+11x-4<0.

    First we determine the solutions of

    3x²+11x-4=0

    Delta=11²-4*3 * (-4) = 121+48=169=13²

    The roots are

    x1 = (-11-13) / 6=-24/6=-4

    x2 = (-11+13) / 6=2/6=1/3

    So, we have:

    3x²+11x-4=3 (x-⅓) (x+4) = (3x-1) (x+4)

    So, coming back to our inequality:

    (3x-1) (x+4) <0, we note (as we already know) that this condition is satisfied for all those x located between the roots: - 4
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