A chemist needs 70 milliliter of 29% solution but has only 19% and 33% solutions available. Find how many milliliter of each that should be mixed to get the desired solution

50 mL of 33% 20 mL of 19%

Step-by-step explanation:

Let x represent the volume in mL of 33% solution needed. Then 70-x is the volume of 19% solution required. The total amount of solute is ...

0.33x + 0.19 (70 - x) = 0.29 (70)

0.14x = 70 (0.29 - 0.19)

x = 70 (0.10/0.14) = 50

50 mL of 33% solution should be mixed with 20 mL of 19% solution to get the desired mix.