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1 June, 22:57

A bag contains 3 red marbles and 6 blue marbles. A second bag contains 6 green marbles and 4 yellow marbles. You choose a marble from bag A and then a marble from bag B, what would be the probability of selecting one blue marble and one yellow marble?

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  1. 2 June, 01:40
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    4/15

    Step-by-step explanation:

    Bag A

    3 red marbles and 6 blue marbles. = 9 marbles

    P (blue) = blue/total = 6/9 = 2/3

    Bag B

    6 green marbles and 4 yellow marbles. = 10 marbles

    P (yellow) = yellow/total=4/10 = 2/5

    P (blue, yellow) = 2/3 * 2/5 = 4/15
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