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9 September, 20:01

Suppose a fair coin is tossed until a head is obtained, and that this experiment is performed independently a second time. What is the probability that the second experiment requires more tosses than the first experiment?

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  1. 9 September, 23:08
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    2/3

    Step-by-step explanation:

    Make X and Y represent the numbers of tosses.

    The probability that X=n is 1/2n,

    the probability that X=n and Y=n is 122n. Sum up, 1 to ∞.

    We get 1/3.

    We have 2/3 divided squarely between X>Y and X
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